3.1324 \(\int \frac {x^2}{a+b x^6} \, dx\)

Optimal. Leaf size=29 \[ \frac {\tan ^{-1}\left (\frac {\sqrt {b} x^3}{\sqrt {a}}\right )}{3 \sqrt {a} \sqrt {b}} \]

[Out]

1/3*arctan(x^3*b^(1/2)/a^(1/2))/a^(1/2)/b^(1/2)

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Rubi [A]  time = 0.01, antiderivative size = 29, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {275, 205} \[ \frac {\tan ^{-1}\left (\frac {\sqrt {b} x^3}{\sqrt {a}}\right )}{3 \sqrt {a} \sqrt {b}} \]

Antiderivative was successfully verified.

[In]

Int[x^2/(a + b*x^6),x]

[Out]

ArcTan[(Sqrt[b]*x^3)/Sqrt[a]]/(3*Sqrt[a]*Sqrt[b])

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 275

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m + 1, n]}, Dist[1/k, Subst[Int[x^((m
+ 1)/k - 1)*(a + b*x^(n/k))^p, x], x, x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]

Rubi steps

\begin {align*} \int \frac {x^2}{a+b x^6} \, dx &=\frac {1}{3} \operatorname {Subst}\left (\int \frac {1}{a+b x^2} \, dx,x,x^3\right )\\ &=\frac {\tan ^{-1}\left (\frac {\sqrt {b} x^3}{\sqrt {a}}\right )}{3 \sqrt {a} \sqrt {b}}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 29, normalized size = 1.00 \[ \frac {\tan ^{-1}\left (\frac {\sqrt {b} x^3}{\sqrt {a}}\right )}{3 \sqrt {a} \sqrt {b}} \]

Antiderivative was successfully verified.

[In]

Integrate[x^2/(a + b*x^6),x]

[Out]

ArcTan[(Sqrt[b]*x^3)/Sqrt[a]]/(3*Sqrt[a]*Sqrt[b])

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fricas [A]  time = 0.89, size = 72, normalized size = 2.48 \[ \left [-\frac {\sqrt {-a b} \log \left (\frac {b x^{6} - 2 \, \sqrt {-a b} x^{3} - a}{b x^{6} + a}\right )}{6 \, a b}, \frac {\sqrt {a b} \arctan \left (\frac {\sqrt {a b} x^{3}}{a}\right )}{3 \, a b}\right ] \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x^6+a),x, algorithm="fricas")

[Out]

[-1/6*sqrt(-a*b)*log((b*x^6 - 2*sqrt(-a*b)*x^3 - a)/(b*x^6 + a))/(a*b), 1/3*sqrt(a*b)*arctan(sqrt(a*b)*x^3/a)/
(a*b)]

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giac [A]  time = 0.16, size = 18, normalized size = 0.62 \[ \frac {\arctan \left (\frac {b x^{3}}{\sqrt {a b}}\right )}{3 \, \sqrt {a b}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x^6+a),x, algorithm="giac")

[Out]

1/3*arctan(b*x^3/sqrt(a*b))/sqrt(a*b)

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maple [A]  time = 0.00, size = 19, normalized size = 0.66 \[ \frac {\arctan \left (\frac {b \,x^{3}}{\sqrt {a b}}\right )}{3 \sqrt {a b}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(b*x^6+a),x)

[Out]

1/3/(a*b)^(1/2)*arctan(1/(a*b)^(1/2)*b*x^3)

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maxima [A]  time = 2.32, size = 18, normalized size = 0.62 \[ \frac {\arctan \left (\frac {b x^{3}}{\sqrt {a b}}\right )}{3 \, \sqrt {a b}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x^6+a),x, algorithm="maxima")

[Out]

1/3*arctan(b*x^3/sqrt(a*b))/sqrt(a*b)

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mupad [B]  time = 0.05, size = 19, normalized size = 0.66 \[ \frac {\mathrm {atan}\left (\frac {\sqrt {b}\,x^3}{\sqrt {a}}\right )}{3\,\sqrt {a}\,\sqrt {b}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(a + b*x^6),x)

[Out]

atan((b^(1/2)*x^3)/a^(1/2))/(3*a^(1/2)*b^(1/2))

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sympy [B]  time = 0.26, size = 56, normalized size = 1.93 \[ - \frac {\sqrt {- \frac {1}{a b}} \log {\left (- a \sqrt {- \frac {1}{a b}} + x^{3} \right )}}{6} + \frac {\sqrt {- \frac {1}{a b}} \log {\left (a \sqrt {- \frac {1}{a b}} + x^{3} \right )}}{6} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2/(b*x**6+a),x)

[Out]

-sqrt(-1/(a*b))*log(-a*sqrt(-1/(a*b)) + x**3)/6 + sqrt(-1/(a*b))*log(a*sqrt(-1/(a*b)) + x**3)/6

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